(Reuters) – Daniil Medvedev was knocked out in the fourth round of Indian Wells by Bulgarian Grigor Dimitrov on Wednesday as the world number two’s near-flawless start turned nightmarish in a 4-6 6-4 6-3 defeat.
Medvedev broke Dimitrov’s serve to open the match, easing through a near-perfect first set in which he won all but four of his first-serve points and fired off three aces with just five unforced errors.
The Russian, who won his maiden major title at the U.S. Open last month, was up two breaks in the second set and seemingly on track for an easy victory.
But Dimitrov came roaring back, winning five games in a row to wrest control of the momentum as Medvedev unravelled, converting on break point to close out the second set, before winning another three games in a row to open the third.
Down 15-40 and 4-1, Medvedev’s frustrations boiled over as he missed a first serve and angrily flung his racquet to the ground. He then double faulted, handing Dimitrov the break.
Medvedev broke back and then held serve, but it was too late, as the world number 28 completed the stunning comeback in the following game, before thrusting his arms aloft in triumph.
(Reporting by Amy Tennery in New York; Editing by Toby Davis)
